[pycrypto] [problem]There's difference between pycrypto to crypt a string and cryptoPP to crypt a string with AES by CFB mode.
myspeme at gmail.com
Mon Dec 28 18:46:20 CST 2009
Thank you, I get the right answer. CryptoPP is default to 128 bit mode. and
I set it to be 8 bit mode and solved.
On Mon, Dec 28, 2009 at 4:32 PM, Dwayne C. Litzenberger <dlitz at dlitz.net>wrote:
> On Mon, Dec 28, 2009 at 02:19:06PM +0800, ten speme wrote:
> >I using cryptoPP to crypt a string with key:"aaaaaaaaaaaaaaa"
> >,iv:"bbbbbbbbbbbbbbbb",data"abcdefghijklmnopqrstuvwxyz", and its encrypted
> >string is [hex]"9FE673D419DD3256B6A206FE7004660F11BAFCE5B2106E2BA39A"
> Please be careful when posting troubleshooting requests. "aaaaaaaaaaaaaaa"
> is 15 bytes long, so it's impossible as an AES key. Can you post example
> code that builds against cryptoPP (or uses pycryptopp) and produces this
> >by pycrypto , I also using the same key, vi, and data. but get difference
> >All these using AES with CFB mode.
> Which CFB mode are you talking about? CFB is a family of modes. You can
> have e.g. 1-bit CFB, 8-bit CFB, 64-bit CFB, 128-bit CFB, etc. PyCrypto
> defaults to 8-bit CFB, I believe, but will accept any multiple of 8 bits.
> (It's set by the segment_size keyword argument to AES.new.)
> Dwayne C. Litzenberger <dlitz at dlitz.net>
> Key-signing key - 19E1 1FE8 B3CF F273 ED17 4A24 928C EC13 39C2 5CF7
> Annual key (2009) - C805 1746 397B 0202 2758 2821 58E0 894B 81D2 582E
> pycrypto mailing list
> pycrypto at lists.dlitz.net
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