[pycrypto] Unicode?

[Dave Pawson]

Now resolved.
Source plain text is created / modified in either DOS or Linux (np to add Mac)

read using
chunk = unicode(infile.read(chunksize))
# replace newline as appropriate
chunk=replaceNL(chunk)
# Convert to byte string
chunk=safe_str(chunk)
encrypt and write to disk


# for decrypt
#Iterate over file to read into string
# replace the individual bytes of the Unicode character (u2022 in my case)
# with \n for the local machine
retval = replaceBullet(retval)

code below

#
#Swap \n for \u2022
#
def replaceNL(str):
    # If DOS, replace \r\x0A
    # If Unix, replace \n
    lineEnd=u'\n'
    if string.find(str,'\r\x0a'):
        lineEnd=u'\r\x0A'
    return string.replace(str,lineEnd,u'\u2022')

#
# Replace bullet by \n
#
def replaceBullet(bstr):
    return string.replace(bstr,u'\\u2022',u'\n')



def safe_str(obj):
    """ return the byte string representation of obj """
    try:
        return str(obj)
    except UnicodeEncodeError:
        # obj is unicode
        return unicode(obj).encode('unicode_escape')

HTH others, though it seems messy, it works.

Dave


On 3 February 2014 09:39, Dave Pawson <dave.pawson at gmail.com> wrote:
> I'm having a problem 'sharing' an encrypted file between
> MSDOS and Linux.
>
> so I thought I'd replace \nl in the plain text with a non ASCII
> character prior to encryption.
>
> encryptor = AES.new(key, AES.MODE_CBC, iv)
> outfile.write(encryptor.encrypt(chunk))
>
> gives me
>
>  File "/usr/lib64/python2.7/site-packages/Crypto/Cipher/blockalgo.py",
> line 244, in encrypt
>     return self._cipher.encrypt(plaintext)
> UnicodeEncodeError: 'ascii' codec can't encode character u'\u2022' in
> position 34: ordinal not in range(128)
>
>
> It would seem I can't use non-ASCII characters, at least with AES, is
> this right ?
>
> If not, how to address it please?
>
>
> regards
>
>
> --
> Dave Pawson
> XSLT XSL-FO FAQ.
> Docbook FAQ.
> http://www.dpawson.co.uk



-- 
Dave Pawson
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