[pycrypto] Unicode?

[Jeremy Gray]

> <grin/>
> Not sure Jeremy! I'd never heard of it.
>

Actually, it looks like 'rU' might be the way to go, not 'Urb'. I've never
used it but probably should. :-)


> I'll let you know.... I'm assuming it is 2.x compatible?
>

yes 2.7, not sure about earlier

--Jeremy




>
> regards
>
> On 3 February 2014 12:40, Jeremy Gray <jrgray at gmail.com> wrote:
> > I may not understand the constraints of your situation, but wouldn't
> > python's "universal newlines" file-open mode achieve what you want?
>  infile
> > = open(filename, 'Urb')
> >
> > --Jeremy
> >
> >
> > On Mon, Feb 3, 2014 at 5:35 AM, Dave Pawson <dave.pawson at gmail.com>
> wrote:
> >>
> >> Now resolved.
> >> Source plain text is created / modified in either DOS or Linux (np to
> add
> >> Mac)
> >>
> >> read using
> >> chunk = unicode(infile.read(chunksize))
> >> # replace newline as appropriate
> >> chunk=replaceNL(chunk)
> >> # Convert to byte string
> >> chunk=safe_str(chunk)
> >> encrypt and write to disk
> >>
> >>
> >> # for decrypt
> >> #Iterate over file to read into string
> >> # replace the individual bytes of the Unicode character (u2022 in my
> case)
> >> # with \n for the local machine
> >> retval = replaceBullet(retval)
> >>
> >> code below
> >>
> >> #
> >> #Swap \n for \u2022
> >> #
> >> def replaceNL(str):
> >>     # If DOS, replace \r\x0A
> >>     # If Unix, replace \n
> >>     lineEnd=u'\n'
> >>     if string.find(str,'\r\x0a'):
> >>         lineEnd=u'\r\x0A'
> >>     return string.replace(str,lineEnd,u'\u2022')
> >>
> >> #
> >> # Replace bullet by \n
> >> #
> >> def replaceBullet(bstr):
> >>     return string.replace(bstr,u'\\u2022',u'\n')
> >>
> >>
> >>
> >> def safe_str(obj):
> >>     """ return the byte string representation of obj """
> >>     try:
> >>         return str(obj)
> >>     except UnicodeEncodeError:
> >>         # obj is unicode
> >>         return unicode(obj).encode('unicode_escape')
> >>
> >> HTH others, though it seems messy, it works.
> >>
> >> Dave
> >>
> >>
> >> On 3 February 2014 09:39, Dave Pawson <dave.pawson at gmail.com> wrote:
> >> > I'm having a problem 'sharing' an encrypted file between
> >> > MSDOS and Linux.
> >> >
> >> > so I thought I'd replace \nl in the plain text with a non ASCII
> >> > character prior to encryption.
> >> >
> >> > encryptor = AES.new(key, AES.MODE_CBC, iv)
> >> > outfile.write(encryptor.encrypt(chunk))
> >> >
> >> > gives me
> >> >
> >> >  File "/usr/lib64/python2.7/site-packages/Crypto/Cipher/blockalgo.py",
> >> > line 244, in encrypt
> >> >     return self._cipher.encrypt(plaintext)
> >> > UnicodeEncodeError: 'ascii' codec can't encode character u'\u2022' in
> >> > position 34: ordinal not in range(128)
> >> >
> >> >
> >> > It would seem I can't use non-ASCII characters, at least with AES, is
> >> > this right ?
> >> >
> >> > If not, how to address it please?
> >> >
> >> >
> >> > regards
> >> >
> >> >
> >> > --
> >> > Dave Pawson
> >> > XSLT XSL-FO FAQ.
> >> > Docbook FAQ.
> >> > http://www.dpawson.co.uk
> >>
> >>
> >>
> >> --
> >> Dave Pawson
> >> XSLT XSL-FO FAQ.
> >> Docbook FAQ.
> >> http://www.dpawson.co.uk
> >> _______________________________________________
> >> pycrypto mailing list
> >> pycrypto at lists.dlitz.net
> >> http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto
> >
> >
> >
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> >
>
>
>
> --
> Dave Pawson
> XSLT XSL-FO FAQ.
> Docbook FAQ.
> http://www.dpawson.co.uk
> _______________________________________________
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>
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